What Is The Kinetic Energy Of A Animal Running At A Rate Of 3.0

A 10.0-kg beast is running at a charge per unit of 3.0 m/s. what is the kinetic energy of the animals

2 answers:

6 0

Given: Mass m= 10.0 Kg; Velocity V = 3.0 thousand/s

Required: Kinetic free energy = K.E = i/2 mV²

G.Eastward = 1/2 (10.0 Kg)(3.0 one thousand/s)²

K.E = 45 J

v 0

Kinetic Energy=1/2 (thou)(v)^2
Yard= 1/ii * 10 * three^2
= 1/two * 10 * 9
= 45 J

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Answer:

the final one

Explanation:

a conclusion is basically a pocket-sized summary at the stop of a passage

The law of conservation of momentum<span> states that for ii objects colliding in an isolated system, the total </span>momentum<bridge> before and afterward the standoff is equal. Momentum should exist conserved. Hope this answers the question. Have a nice twenty-four hour period.</span>

Since Jim's speed is abiding and he is moving in a straight line, he is not accelerating, and we know the net force on him is zero. There is no Forcefulness anywhere doing any piece of work. And then no power is being added to him or dissipated past him.

Answer:

$2.0 m/s^2$

Explanation:

The figure is not provided and we don't know the forcefulness applied to the books.

Therefore, here we are going to assume the forcefulness applied is 3 N:

F = 3 N

We can discover the acceleration of the stack of books by using Newton'south second law of motion, which states that the net force on an object is equal to the product between its mass and its acceleration:

$F=ma$

where

F is the strength

m is the mass

a is the acceleration

In this trouble we take

m = 1.5 kg is the mass of the books

Therefore, the acceleration is:

$a=\frac{F}{m}=\frac{3.0}{1.5}=2.0 m/s^2$

Reply:

The piece of work done on the gas = 2PV

Explanation:

In this question, we need to apply the basic gas laws to determine the discussion done.

For this question, nosotros need to draw a PV diagram (a pressure-volume diagram), which I have fabricated and attached in the attachment. Then please refer to that attachment. I will be using this diagram to solve for the piece of work done on the gas.

So, Delight refer to the zipper number 1. where 10 -centrality is of volume and y-axis is of force per unit area.

As we know that, the work done on the gas is equal to the area nether the bend.

W = Area of the triangle

W = 0.5 x ( base) x ( height)

W = 0.v 10 (BC) x (Air conditioning)

W = 0.5 10 (3V-V) x (3P-P)

Westward = 2PV

Hence, the work done on the gas = 2PV